Loading [MathJax]/jax/output/HTML-CSS/jax.js

User Tools

Site Tools


pow:problem1f24

Problem 1 (due on Monday, September 9)

Find all natural numbers n>1 such that 2!+3!++n! is a cube of an integer.

The problem was solved by Sasha Aksenchuk, Prof. Vladislav Kargin, Josiah Moltz, and Mithun Padinhare Veettil. The only solution is n=3. All solutions received and our in-house solution are based on the observation that a cube of an integers must yield a remainder 0, 1, or 6 when divided by 7. For a detailed solution see the following link Solution.

pow/problem1f24.txt · Last modified: 2024/09/10 00:47 by mazur