Activities
Student Organizations
Math Club
BingAWM
Actuarial Association
Problem 1 (due on Monday, September 9)
Find all natural numbers n>1 such that 2!+3!+…+n! is a cube of an integer.
The problem was solved by Sasha Aksenchuk, Prof. Vladislav Kargin, Josiah Moltz, and Mithun Padinhare Veettil. The only solution is n=3. All solutions received and our in-house solution are based on the observation that a cube of an integers must yield a remainder 0, 1, or 6 when divided by 7. For a detailed solution see the following link Solution.