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pow:problem5s26
Problem 5 (due Monday, April 13)
Prove that \[\sum_{k=0}^{n}{3n\choose 3k }=\frac{2}{3}\left( 2^{3n-1}+(-1)^n\right). \]
pow/problem5s26.txt · Last modified: 2026/04/12 21:46 by mazur