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pow:problem1s22

Problem 1 (due on Monday, February 14)

Let f:(0,)R be a continuously differentiable function such that limx(f(x)+2f(x))=1. Prove that limxf(x)=0.

We received a solution from Ashton Keith. Ashton's ideas are similar to our second solution, but his solution lacks sufficient rigor. For detailed solution see the following link Solution.

pow/problem1s22.txt · Last modified: 2022/02/15 01:00 by mazur