pow:problem1f25
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| + | <box 85% round orange| | ||
| + | A point $P$ inside a convex quadrilateral $ABCD$ is such that the triangles $ABP$, $BCP$, $CDP$, $ADP$ | ||
| + | have all the same area. Prove that one of the diagonals halves the area of the quadrilateral. | ||
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| + | </ | ||
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| + | We received solutions from Raisha Chowdhury, Gerald Marchesi, Josiah Moltz, and Mathew Wolak. | ||
| + | The solution submitted by Gerald Marchesi is particularly simple assuming familiarity with the concept | ||
| + | of cross product of vectors in $\mathbb R^3$. For details and other solutions see the following link {{: | ||
