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Problem 4 (due Monday, October 25)

a) Let x1,,xn be real numbers. Prove that ni=1nj=1sin(xixj)xixjni=1nj=1sin(xi+xj)xi+xj with the convention that sinxx=1 when x=0.

b) Compute 10sin2xsin5x dx.

The problem was solved by Ashton Keith. Ashton's solution is similar to our solution. For details see the following link Solution.